- #1
bullroar_86
- 30
- 0
I have a similar question to this, and I'm trying to figure out how it works. I think the answer here might be wrong.
It won't copy/paste right so here's the link
http://www.physics.ohio-state.edu/~gan/teaching/spring99/C13.pdf
A nonuniform bar of weight W is suspended
at rest in a horizontal position by two massless
cords. One cord makes the angle q = 36.9° with
the vertical; the other makes the angle f = 53.1°
with the vertical. If the length L of the bar is 6.10
m, compute the distance x from the left-hand end
of the bar to its center of mass.
When i plug in the values, I'm getting 2.19
the answer there is 2.93
It won't copy/paste right so here's the link
http://www.physics.ohio-state.edu/~gan/teaching/spring99/C13.pdf
A nonuniform bar of weight W is suspended
at rest in a horizontal position by two massless
cords. One cord makes the angle q = 36.9° with
the vertical; the other makes the angle f = 53.1°
with the vertical. If the length L of the bar is 6.10
m, compute the distance x from the left-hand end
of the bar to its center of mass.
When i plug in the values, I'm getting 2.19
the answer there is 2.93