- #1

bullroar_86

- 30

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It won't copy/paste right so here's the link

http://www.physics.ohio-state.edu/~gan/teaching/spring99/C13.pdf

A nonuniform bar of weight W is suspended

at rest in a horizontal position by two massless

cords. One cord makes the angle q = 36.9° with

the vertical; the other makes the angle f = 53.1°

with the vertical. If the length L of the bar is 6.10

m, compute the distance x from the left-hand end

of the bar to its center of mass.

When i plug in the values, I'm getting 2.19

the answer there is 2.93