Application of Differentiation Problem

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Here's a problem that I just found in my book and to my dismay, I couldn't figure out how differentiation can be used to solve a particular problem (seeing how we've just finished this unit at school). So here's the problem:

Felicity and Jane start alking at the same time towards an intersection of two roads that meet at right angles.

http://img528.imageshack.us/img528/66/untitledfh4.png [Broken]

Felicity starts at 9km from the intersection while Jane starts at 13km from the intersection. Their speeds are 4 km/h and 3 km/h respectively. What is the closest that Felicity and Jane will get?

I cannot figure out how to relate the two into one equation. Obviously, we need an equation for the distance between them and find the minimum for it (i.e. f'(x) = 0). Anyway, I thought I got differentiation down pat but ... guess not :frown:
 
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arildno

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Well, denote Felicity's position VECTOR as a function of time:
[tex]\vec{r}_{F}(t)=(x_{F}(t),y_{F}(t))[/tex]
and similarly, for Jane:
[tex]\vec{r}_{J}(t)=(x_{J}(t),y_{J}(t))[/tex]

now, choose an intelligent origin, specify the component functions, and find an expression for the distance between them, as a function of time.
 
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I haven't learned anything about vectors but I think I've got it. x = Felicity's distance to the intersection while y = Jane's distance to the intersection.

http://img379.imageshack.us/img379/5775/problemns7.jpg [Broken]

So the closest they can get is 5 km :smile: Phew, haven't lost my touch yet. Thanks anyway arildno!

Hmm I wonder why the images won't actually show up ...
 
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