Application of Differentiation Problem

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SUMMARY

The discussion focuses on a differentiation problem involving two individuals, Felicity and Jane, who start walking towards an intersection from different distances and speeds. Felicity is 9 km away from the intersection and walks at 4 km/h, while Jane is 13 km away and walks at 3 km/h. The key conclusion is that the closest distance they will reach is 5 km, determined by formulating their positions as vectors and finding the minimum distance function through differentiation.

PREREQUISITES
  • Understanding of basic differentiation principles
  • Knowledge of vector representation in mathematics
  • Familiarity with distance formula in a two-dimensional space
  • Ability to solve equations for minimum values
NEXT STEPS
  • Study vector calculus and its applications in motion problems
  • Learn about optimization techniques in calculus
  • Explore the distance formula in coordinate geometry
  • Practice solving real-world problems using differentiation
USEFUL FOR

Students studying calculus, particularly those interested in applications of differentiation in motion problems, as well as educators looking for practical examples to illustrate vector concepts.

bjgawp
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Here's a problem that I just found in my book and to my dismay, I couldn't figure out how differentiation can be used to solve a particular problem (seeing how we've just finished this unit at school). So here's the problem:

Felicity and Jane start alking at the same time towards an intersection of two roads that meet at right angles.

http://img528.imageshack.us/img528/66/untitledfh4.png

Felicity starts at 9km from the intersection while Jane starts at 13km from the intersection. Their speeds are 4 km/h and 3 km/h respectively. What is the closest that Felicity and Jane will get?

I cannot figure out how to relate the two into one equation. Obviously, we need an equation for the distance between them and find the minimum for it (i.e. f'(x) = 0). Anyway, I thought I got differentiation down pat but ... guess not :frown:
 
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Well, denote Felicity's position VECTOR as a function of time:
[tex]\vec{r}_{F}(t)=(x_{F}(t),y_{F}(t))[/tex]
and similarly, for Jane:
[tex]\vec{r}_{J}(t)=(x_{J}(t),y_{J}(t))[/tex]

now, choose an intelligent origin, specify the component functions, and find an expression for the distance between them, as a function of time.
 
I haven't learned anything about vectors but I think I've got it. x = Felicity's distance to the intersection while y = Jane's distance to the intersection.

http://img379.imageshack.us/img379/5775/problemns7.jpg

So the closest they can get is 5 km :smile: Phew, haven't lost my touch yet. Thanks anyway arildno!

Hmm I wonder why the images won't actually show up ...
 
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