Application of Stokes' Theorem

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Homework Statement


Solve the following question by using Stokes' Theorem.

(Line integral on C) 2zdx + xdy + 3ydz = ? where C is the ellipse formed by
z = x, x^2 + y^2 = 4.

Homework Equations





The Attempt at a Solution



We have the vector A=(2z,x,3y) which is cont. differentiable and
curl(A) = (3,2,1). Now we have to parametrize the smooth surface S whose boundary is C and obtain a normal. I'm confused here how to choose the parameters. I solved it using the usual way and got -8*Pi. Can you help me to arrange the double integral in order to solve it by using Stokes' Thm.? Thanks.
 
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The normal to the ellipse is the same as the normal to the plane x=z. So it's a constant vector. Your curl is also a constant vector. So the integrand of the double integral is just a constant. This means you only need to know the area of the ellipse and the value of the integrand. No need to actually integrate anything.
 
Okay, i got it. The normal to the plane is n=(1,0,-1) but we need an outward normal so we take n=(-1,0,1). We get (3,2,1)(-1,0,1) = -2. Projection onto xy-plane is a circle whose area is 4*Pi and multiplying it by -2 we obtain 8*Pi.
 
I guess I would normalize the normal by dividing by sqrt(2) and then multiply by the real area of the ellipse which is sqrt(2) times the area of the circle. But of course, you get the same thing.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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