Applications of integration - volume of volcanic ash

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SUMMARY

The discussion revolves around calculating the total volume of volcanic ash that falls within 1 km of a volcano, modeled by the function exp(-r^2) for ash depth at distance r. The user initially attempted to apply solid revolution techniques but faced challenges integrating with respect to the correct variable. The solution requires recognizing the appropriate coordinate system and integrating the volume using cylindrical coordinates, specifically focusing on the radius defined by the ash depth function.

PREREQUISITES
  • Understanding of solid revolution concepts in calculus
  • Familiarity with integration techniques, particularly in cylindrical coordinates
  • Knowledge of exponential functions and their properties
  • Ability to visualize and interpret geometric shapes formed by integration
NEXT STEPS
  • Study the method of cylindrical shells for volume calculations
  • Learn about integrating exponential functions in calculus
  • Explore applications of integration in real-world scenarios, such as environmental modeling
  • Practice problems involving solid revolutions and volume calculations
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Students studying calculus, particularly those focusing on applications of integration, as well as educators looking for examples of real-world integration problems related to environmental science.

Anabelle37
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Homework Statement



After a volcanic eruption, the ash gradually falls to the ground euqally in all directions. the depth of the ash diminishes with the distance from the volcano such that at a distance r metres the depth is exp(-r^2). find the total volume of ash falling within 1 km of the volcano.

The Attempt at a Solution



We've been doing solid revolutions in class for applications of integration. I tried to do this question by partitioning the y-axis so i could revolve aroung the y-axis to form a volume.
I called the radius exp(-r^2) and therefore my volume of my disc is pi*exp(-2r^2)*Delta(y). Then i realized that I couldn't integrate it from r=0 to r=1000 as my partition was for y not x. but partitioning x wouldn't seem correct. So now I'm completely stuck!

Any pointers would be great!
Is there another way to do it?

Thanks
 
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Hi Anabelle! :smile:

(have a pi: π and a delta: ∆ and try using the X2 icon just above the Reply box :wink:)

erm :redface: … there are coordinates other than x and y ! :wink:

try using r :smile:
 

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