zcabral Messages 30 Reaction score 0 Thread starter May 8, 2008 #1 Homework Statement Length of curve: y=1/2(ex-e-x) from 0 to 2 Homework Equations s = ∫√[1+(dy/dx)^2] dx The Attempt at a Solution [sqrt(4+2e^(-x)+e^x)]*[-1+e^x]/[1+e^x]. = 3.323971
Homework Statement Length of curve: y=1/2(ex-e-x) from 0 to 2 Homework Equations s = ∫√[1+(dy/dx)^2] dx The Attempt at a Solution [sqrt(4+2e^(-x)+e^x)]*[-1+e^x]/[1+e^x]. = 3.323971
Hootenanny Staff Emeritus Science Advisor Gold Member Messages 9,621 Reaction score 9 May 8, 2008 #2 Your notation is ambiguous. I'm guessing that your curve is, [tex]y(x) = \frac{e^x-e^{-x}}{2}[/tex] In which case it may be useful to note that, [tex]\frac{e^x-e^{-x}}{2} = \sinh(x)[/tex] Which (along with a hyperbolic identity) would greatly simplify your integrand.
Your notation is ambiguous. I'm guessing that your curve is, [tex]y(x) = \frac{e^x-e^{-x}}{2}[/tex] In which case it may be useful to note that, [tex]\frac{e^x-e^{-x}}{2} = \sinh(x)[/tex] Which (along with a hyperbolic identity) would greatly simplify your integrand.