Archimedes (Buoyant force) Not EZ

AI Thread Summary
The discussion revolves around proving the formula for calculating the density of a rock using buoyant force principles. The user presents a scenario involving a rock attached to a string, with specific tension values in and out of water. The formula to be proven is derived from the relationship between the weight of the rock in air and its weight when submerged, factoring in the density of water. The user seeks assistance in demonstrating why this formula is valid, emphasizing the need for a clear understanding of the underlying physics, particularly through free-body diagrams and net force calculations. The goal is to validate the formula for density based on the principles of buoyancy.
Jguth
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I tryied but failed miserabely, i need to prove this formula!


Archimedes (Buoyant force)

Lets say that a rock is attatched to a string, the string has a tention of 5.0N out of the water, and has a tention of 3.2N submerged in water. Now to find the density of the rock, the formula used is:


p rock=(5.0/5.0-3.2)p water


To explain...

density of rock=(wt in air/ wt in air-wt in water)*density of water


Now i need to prove this formula, i would apreciate any help, thanks

Note:
(p=density)

What i know:
p=mv
Density of water is 1000kg/m^2

I tried many different ways but never got a definite answer
 
Last edited:
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You can start by drawing the freebody diagram for the rock, and calculate the net force on the rock in and out of the water.
 
I know all that, i know the density of the rock and everything, i just need to prove the formula (show why it works)
 
i need to prove

density of rock=(wt in air/ wt in air-wt in water)*density of water
 
Start from lost weight in water = buoyant force of water = ...
 
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