Are (A then B) then C and (A and B) then C equivalent?

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The discussion focuses on proving the equivalence of the logical expressions (A then B) then C and (A and B) then C. A truth table is suggested as the simplest method for this proof, with 23 combinations of truth values for A, B, and C. The equivalence is established if both expressions yield the same truth values across all combinations. The user is advised to analyze the eight possible scenarios using True (T) and False (F) values. This method will clarify whether the two statements are indeed equivalent.
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I need help proving that (A then B) then C and (A and B) then C are equivalent. Can anyone help?
 
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This doesn't meet criterai for posting in Philosophy. If this is homework, please post in the appropriate Homework forum
 
I am moving this to the "precalculus homework" forum.

Gamecock Girl, I think the simplest way to do this is to use a "truth table". There are 23 different ways A, B, and C can be "True" or "False". The two statements are equivalent if they are both True or both False in each of those.

Writing "T" for True, "F" for False and "ABC" in that order, the 8 ways are:
TTT, TTF, TFT, TFF, FTT, FTF, FFT, FFF. Assuming you know what "if (if A then B) then C" and "if (A and B) then C" mean, you can decide whether they are True of False in each of those 8 situations.
 

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