Are Commutative Matrices the Key to Solving These Matrix Equations?

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The discussion revolves around proving that if two matrices A and B commute (BA=AB), then specific matrix equations hold true. The first equation, (A+B)^2, simplifies to A^2 + 2AB + B^2 when A and B are commutative. The second equation, (A+B)^3, also holds true and simplifies to A^3 + 3A^2B + 3AB^2 + B^3 under the same condition. Participants engage in expanding and simplifying the expressions to reach these conclusions. The thread concludes with affirmation of the correct application of matrix properties in these proofs.
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Homework Statement



Proof that if two matrices A and B are commutative, BA=AB, then the equations:

a) (A+B)^2 = A^2 + 2AB + B^2 ; b)(A+B)^3=A^3+3A^2B+3AB^2+B^3

are true.

Homework Equations





The Attempt at a Solution

 
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Have you tried anything? What do you get if you explicitly expand out the brackets in each case? What happens in the case of A and B commuting?
 
I don't know what do you mean?
 
Theofilius said:
I don't know what do you mean?

What do you get when you multiply out (A+B)(A+B), where A and B are matrices?
 
cristo said:
What do you get when you multiply out (A+B)(A+B), where A and B are matrices?

I get
(A+B)(A+B)=A^2+AB+BA+B^2
 
Theofilius said:
I get
(A+B)(A+B)=A^2+AB+BA+B^2

Good, now can you simplify this in the case that A and B commute?
 
cristo said:
Good, now can you simplify this in the case that A and B commute?


(A+B)^2=(A+B)(A+B)=A^2+AB+BA+B^2=A^2+2AB (or 2BA) + B^2

like this?
 
Theofilius said:
(A+B)^2=(A+B)(A+B)=A^2+AB+BA+B^2=A^2+2AB (or 2BA) + B^2

like this?

Correct!

Now, try applying similar techniques to the second question.
 
(A+B)^3=(A+B)(A+B)(A+B)=(A^2+2AB+B^2)(A+B)=A^3+A^2B+2A^2B+2AB^2+B^2A+B^3=A^3+A*AB+2A*AB+2<br /> <br /> AB*B+B*BA+B^3
=A^3+3A^2B+3AB^2+B^3

Something like this?
 
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*Applause*

Huzza, well done!
 
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