InvariantBrian said:
Newton's three laws are;
1. Inertia
2. f=ma
3. for every action there is an equal an opposite reaction.
It seems to me that the first and third law are still valid with the theory of relativity. And the second law f=ma is generally true in so far as it is correct to say that there exists an invariant universal relation between force mass and acceleration. Newton did not know that time, space and mass vary with respect to velocity. But I am inclined to say that Newton's ideas were incomplete rather than simply wrong. I am interested in what others may have to say about this.
Thanks
Brian.
In going to special relativity;
First Law - Newton's first law remains valid.
Second Law - The second law remains valid as well. However you wrote it down incorrectly. Newton's second law is
not F = ma. Its F = dp/dt. Only when m = constant does F = ma. Even Newton didn't hold that F = ma. Newton held that force is proportional to changes in momentum. In SR Inertia is properly though of as a bodies resistance to changes in momentum.
The definition of momentum remains valid as well. I.e. momentum is still given by p = mv. For tardyons (particles for which v < c) m = m(v) = m
0/(1 - v
2/c
2)
1/2 where m
0 = m(0) (m
0 is what pervect labels "m"). m
0 is called
proper mass or sometimes
rest mass (I dislike the term "rest mass" myself). For a derivation please see
http://www.geocities.com/physics_world/sr/inertial_mass.htm
If anyone notices any errors on this page please let me know. Thanks.
Third Law - Newton's Third Law is not always valid even in non-relativistic physics. It sometimes fails when there are charges involved. But in SR it always holds for contact forces.
Note - Everything above applies to particles. If the object in question is not a particle then
p = m
0v/(1 - v
2/c
2)
1/2 is not always valid. For example, a rod which is moving in the direction parallel to its length. If the rod is loosing mass uniformly in its rest frame (e.g. by emitting radiation uniformly along its length) then
p = m
0v/(1 - v
2/c
2)
1/2 does not hold. The relationship is more complicated. See the bottom of this page
http://www.geocities.com/physics_world/sr/invariant_mass.htm
If the mass of the rod is constant but is under stress then the momentum not given by
p = m
0v/(1 - v
2/c
2)
1/2 either. Stress adds to inertial mass but it only does so when the body is moving. For an example which will shed light on this see
http://www.geocities.com/physics_world/sr/rd_paradox.htm
I'm working on another example but I've put it aside for the time being. I'll get back to it next year.
Pete