Area bounded by Curves Integration Question

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Homework Statement



Find the region bounded by the two functions from y=0 to y=2

equations given:
x=(y-1)2 -1
x=(y-1)2 +1

express x as a function of y and integrate it with respect to y

Homework Equations



equations given:
x=(y-1)2 -1
x=(y-1)2 +1


The Attempt at a Solution



Set x as a function of y

sqrt(x+1) + 1 =y
sqrt(x-1 ) + 1 = y

4. The confusion

The second equation doesn't actually exist until x =1...does that mean I have to just integrate from 1 to 2? But...

It says from y=0 to y=2... I am confused about this. I am told to express x as a function of y and integrate it with respect to y... I am unclear as to the meaning of this. It would make more sense if this was x=0 to x=2... please help!
 
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Okay, I think the two equations you have are:
##x=(y-1)^2-1##
##x=(y-1)^2+1##

Think about the wording: "express x as a function of y", this means that you aren't supposed to change the equations because x should be isolated, and it already is. Remember now that when you are integrating a function ##x=f(y)## that the bounds of integration will be from ##y=a## to ##y=b##, not X's.

So you don't have the manipulate the equations because x is already isolated, can you see where to go on from here?
 
Ahhh yes! Thank you! The wording confused me greatly; I think that was the problem. Thank you for your time.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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