What is the Area of the Region Bounded by y = 3x^2-3, x = 0, x = 2, and y = 0?

disk256
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The area of the region bounded by the curve y = 3x^2-3 , the y-axis, x-axis, and the line
x = 2 is equal to

so far i ve managed to draw the graph i m getting a value of 9

is that correct
 
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disk256 said:
The area of the region bounded by the curve y = 3x^2-3 , the y-axis, x-axis, and the line
x = 2 is equal to

so far i ve managed to draw the graph i m getting a value of 9

is that correct
Are you sure this is the exact wording of the problem? It's not clear to me what the region looks like.
 
Do you mean this region?
 

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Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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