Area Calculation for Parametric Equation: x=t^3-5t, y=7t^2

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Homework Statement


Find the area of the region enclosed by the parametric equation
x=t^3-5t
y=7t^2


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The Attempt at a Solution


I know how you set it up \int (7t^2)(3t^2-5)dt, but how do you find the bounds. I tried finding t and got t= (+/-)\sqrt{y/7} and you plug it into x but where do you go from there.
 
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What I understand by enclosed means for the value of t where x=0. So the values are x=-\sqrt{5} , 0 , \sqrt{5} So I guess you have to find two integrals, for x>0 and for x<0 because one will get negative and the other positive and to add them.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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