Triangle Area Calculation: Base 2 & 3/4, Height 4/9 | 11/18 Solution

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The area of a triangle with a base of 2 and 3/4 and a height of 4/9 is calculated using the formula 1/2 * (b*h). The correct calculation yields an area of 11/18. Confirmation of the solution indicates that the approach taken is valid. It is important to ensure that the height is perpendicular to the base for accurate results. The discussion emphasizes the need for clarity in defining the height in relation to the base.
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Homework Statement



area of triangle with a base of: 2 & 3/4
and a height of 4/9

Homework Equations



1/2 * (b*h)

The Attempt at a Solution



i used:
1/2*(11/4 * 4/9) = 44/72 = 22/36 = 11/18
 
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rcmango said:

Homework Statement



area of triangle with a base of: 2 & 3/4
and a height of 4/9

Homework Equations



1/2 * (b*h)

The Attempt at a Solution



i used:
1/2*(11/4 * 4/9) = 44/72 = 22/36 = 11/18
What you've done is correct given how you've described the problem. Are you just unsure about your answer? Because it's right.
 
Yeah, I just want to make sure I was solving these problems correctly, and I had to have a confirm :) ,thankyou!
 
rcmango said:
Yeah, I just want to make sure I was solving these problems correctly, and I had to have a confirm :) ,thankyou!

Just make sure the height is perpendicular (right angled) to the base. If you're taking the height as being slanted to the base, such as having an equilateral triangle with the length of a side given, you can't just say the height is the same length as the base.
 
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Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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