Area Under The Graph (Quick Question)

[Incog]

So I have a velocity-time graph and I need to calculate the area under it. I guess the "shape" made is a triangle so the formula would be 0.5 x b x h. But what exactly is the area under the graph supposed to represent? Does it have anything to do with position?

Thanks in advance.

 

[chuy]

If the function of you graphic is f(x), the area is:

A=\int f(x) dx

If f(x)=mx +b :

A=\int (mx +b)dx

A= \frac{1}{2}mx^2+bx

See: http://en.wikipedia.org/wiki/Integral

I hope to have helped

 

[courtrigrad]

the area under the graph of a velocity-time graph, is the total displacement of a body.

 

[konichiwa2x]

the area under a speed-time graph gives the total distance travelled by the body.
the area under a velocity-time graph gives the total displacement of the body.