Arranging resistors to have a minimum equivalent

AI Thread Summary
The minimum equivalent resistance from connecting 50 resistors of 0.25 ohms each is achieved by arranging them in parallel. The correct calculation leads to an equivalent resistance of 1/200 ohms, confirming option D as the answer. Participants in the discussion highlight the importance of careful calculations to avoid errors. The consensus is that the parallel arrangement is indeed the correct method for minimizing resistance. Overall, the discussion emphasizes the need for accuracy in applying the formulas for resistor arrangements.
Tanishq Nandan
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Homework Statement



The minimum resistance obtained by connecting 50 resistances of 0.25 ohm each is
A)50/4ohm B)4/50 ohm C)200 ohm D)1/200 ohm
2.Relevant equations
1.When resistances are connected in series,
▪R(equivalent)=summation of all individual resistances
2.When resistances are connected in parallel ,
▪1/(equivalent resistance) =1/(summation of reciprocals of individual resistances)

The Attempt at a Solution


Minimum resistance is usually obtained when all resistances are connected in parallel (better than adding them all up).
So,it should be coming as 4/50 ohms,using formula 2,but the answer is given as D,1/200 ohms.

How do you arrange these resistors to have an equivalent resistance of 1/200 ohms??
 
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You have made a simple math error. Slow down and do it again. Show more intermediate steps if you want to know exactly which step is in error.
Tanishq Nandan said:
How do you arrange these resistors to have an equivalent resistance of 1/200 ohms??
You were correct when you said they should all be in parallel.
 
I got D as well. Check your calculations.
 
Yeah,got it,dumb me.Thanks,guys..
 
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