Asked in calc area, wasn't answered

  • Thread starter Thread starter relskid
  • Start date Start date
  • Tags Tags
    Area
Click For Summary
SUMMARY

The discussion focuses on calculating the volume of solids generated by rotating a circle and determining fluid force on a cylindrical gasoline tank. The first problem involves using the disk method and the shell method for the equation (x-10)² + y² = 36, with the integral setup confirmed as π∫(36 - (x-10)²)dx. The second problem requires applying the fluid force formula F = ∫(p)(h(y))(L(y))dy for a half-full cylindrical tank with a diameter of 2 feet, where the weight of gasoline is 42 pounds per cubic foot. The discussion emphasizes the importance of choosing the correct method based on the orientation of the representative rectangle.

PREREQUISITES
  • Understanding of integral calculus and volume calculations
  • Familiarity with the disk and shell methods for volume of revolution
  • Knowledge of fluid mechanics, specifically fluid force calculations
  • Ability to manipulate and evaluate definite and indefinite integrals
NEXT STEPS
  • Study the Shell Method for calculating volumes of solids of revolution
  • Learn about the Disk Method and its applications in volume calculations
  • Explore fluid mechanics principles related to pressure and force on submerged surfaces
  • Practice solving integrals involving square roots and polynomial expressions
USEFUL FOR

Students in calculus courses, educators teaching volume and fluid mechanics, and anyone seeking to enhance their understanding of integration techniques in real-world applications.

relskid
Messages
32
Reaction score
0

Homework Statement



find the volume of the solid generated by rotating the circle (x-10)^2 + y^2 = 36 about the y-axis


Homework Equations



disk method: [tex]\pi\int [R(x)]^2dx[/tex]

shell method: [tex]2\pi\int (x)(f(x))dx[/tex]


The Attempt at a Solution



[tex]y = \sqrt{36-(x-10)^2}dx[\tex]<br /> <br /> \\\pi\int [(\sqrt{36-(x-10)^2})]^2dx[/tex]

[tex]\pi\int (36-(x-10)^2)dx[/tex]

[tex]\pi\int (36-(x^2-20x-100))dx[/tex]

[tex]\pi\int (-x^2+20x-64)dx[/tex]

[tex]\pi [(\frac{-x^3}{3}+10x^2-64x)][/tex]

ok, as you may have noticed, the integral isn't definite. that's because i don't know whether it should be from 4 to 16, or -6 to 6. also, if i did the entire problem wrong, that'd be nice to know, too. :P


next problem:

Homework Statement



a cylindrical gasoline tank is placed so that the axis of the cylinder is horizontal. find the fluid force on a circular end of the tank if the tank is half full, assuming that the diameter is 2 feet and the gasoline weighs 42 pounds per cubic foot.


Homework Equations



[tex]F =\int (p)(h(y))(L(y))dy[/tex]

p=rho (density)

The Attempt at a Solution



[tex]x^2 + y^2 = 2^2[/tex]

[tex]x^2 = 4 - y^2[/tex]

[tex]x = \sqrt{4 - y^2}[/tex]

note: integration from -1 to 0

[tex]42\int(-y)\sqrt{4 - y^2}dy[/tex]

after that, i don't really know what to do. this is the part that I'm especially not sure about:

[tex]-42\int(y)\sqrt{4 - y^2}dy[/tex]

[tex]u=4-y^2[/tex]

[tex]du=-2ydy[/tex]

[tex]-\frac{1}{2}du=ydy[/tex]

[tex]-42(-\frac{1}{2})\int\sqrt{u}du[/tex]

[tex]21\int\sqrt{u}du[/tex]

[tex]21[\frac{u^\frac{3}{2}}{3/2}][/tex]


thanks to any who can help.
 
Physics news on Phys.org
Problem #1: from what you have you are using the disk method, which means you would have to switch variables (solve for x) and then it becomes kind of messy. Instead, use Shell method and use symmetry of the problem or you would need to do 2 integrals. That way you can use the way you did in terms of y = Sqrt(36-(x-10)^2). You'll see the limits right away when you draw it out. Hope that helps...hope I'm right as well.

If the representative rectangle is perpendicular to the axis of revolution, use the disk method.
If the representative rectangle is parallel to the axis of revolution, use the shell method.
 

Similar threads

  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
6
Views
1K
Replies
64
Views
6K
Replies
15
Views
3K
Replies
1
Views
1K
  • · Replies 17 ·
Replies
17
Views
2K
Replies
6
Views
2K
Replies
3
Views
2K