Astrophysics - elliptical orbit proof help.

AI Thread Summary
The discussion focuses on proving the equation of an ellipse and its area. Participants confirm that the standard equation for an ellipse centered at the origin is x^2/a^2 + y^2/b^2 = 1, where a and b represent the semi-major and semi-minor axes, respectively. They also explore how to derive the area of the ellipse, A = πab, through integration techniques. The conversation highlights the importance of understanding the relationship between the ellipse's parameters and the integration process needed to verify the area formula. Overall, the thread emphasizes foundational concepts in astrophysics related to elliptical orbits.
Kiwithepike
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A.)
Assume a rectangular coord system has its origin at the center of an elliptical planetary orbit and that the coord system x-axis lies along the major axis of the ellipse. Show that the equation for the ellipse is given by x^2/a^2 + y^2/b^2 =1.
where a and b are the lengths if the semi-major axis and the semi-minor axis, respectively.

b.)
using the results from a, prove the area of an ellipse is given by A=(pi)ab.

Im am completely lost right now. Any ideas?
 
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For starters, what facts do you know about an ellipse that you could use in the proof?
 
(x-h)^2/a^2 + y-k)^2/b^2=1

c^2= a^2 -b^2

while a ≥b>0
 
OK, well for part a, for the ellipse in question, what would h and k be?
 
zero, so (x-h)^2 = x^2 and (y-k)^2= y^2 right?
 
Right, so that part's done. (Although it seems really simple, are you sure you can use that equation as a starting point?)

Now what about part b? How could you find area?
 
thats what the text tell you to use. That does seem really simple, maybe that's why I am so lost.

B) i know the area A=piab
so the way i was looking at it
solve for y? then integrate it, with trig sub get pi ab?
 
Yep, sounds like you're on the right track with that. (Obviously make sure you actually do it to verify that you get the right answer)
 
Thank you so much for your help
 
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