Asymmetrical charged parallel plates capacitor

AI Thread Summary
In a parallel plate capacitor with one plate charged and the other neutral, the potential difference can be calculated using the formula V = Q/C, where Q is the charge and C is the capacitance. Grounding the neutral plate allows it to gain charge, effectively neutralizing the positive charge on the other plate. When a charged conductor is brought near an uncharged one and the uncharged conductor is earthed, it can acquire a charge through induction. The discussion emphasizes the importance of visualizing the charge distribution on the plates to understand the effects of grounding. Overall, grounding alters the charge distribution and potential difference in the capacitor setup.
abdo799
Messages
168
Reaction score
4
If i have a parallel plates capacitor , where the plates have different charges , eg, one plate has 1 C of charge and the other is neutral , what's the potential difference? what if i grounded the neutral plate , will it gain 1 C of charge?
 
Physics news on Phys.org
What normally happens when a charged conductor is brought close to an uncharged conductor... and then you Earth the uncharged conductor?
 
Simon Bridge said:
What normally happens when a charged conductor is brought close to an uncharged conductor... and then you Earth the uncharged conductor?

yea, just like charging by induction , but about the charge i use to find out the V using CV=Q , should i use the mean of the sum of the absolute values of both charges?
 
There's a fairly decent description here:
http://physics.stackexchange.com/questions/101116/capacitor-with-different-charges-on-each-plate

If you sketch out the situation - careful to draw the plates as having a thickness - you should see how to deal with it.
The "top" plate has a single row of +++++ across the lower surface, there's a gap, and the bottom plate has a row of ------- (minuses) along the top and ++++++ along the bottom. What does that look like to you?

If you ground the bottom plate, you get rid of the ++++ on the bottom.
 
  • Like
Likes 1 person
Thread 'Motional EMF in Faraday disc, co-rotating magnet axial mean flux'
So here is the motional EMF formula. Now I understand the standard Faraday paradox that an axis symmetric field source (like a speaker motor ring magnet) has a magnetic field that is frame invariant under rotation around axis of symmetry. The field is static whether you rotate the magnet or not. So far so good. What puzzles me is this , there is a term average magnetic flux or "azimuthal mean" , this term describes the average magnetic field through the area swept by the rotating Faraday...
Back
Top