Atmospheric Pressure: Solving with a Mercury Barometer

AI Thread Summary
The discussion centers on calculating atmospheric pressure using a mercury barometer with a height of 750 mm at 25°C. The formula Patm = ρ*g*H0 is applied, leading to a calculation of 99914.85 kg/s²*m. There is confusion regarding unit conversion, specifically how this result translates to 99.54 kPa as stated in the textbook. It is clarified that 1 Pascal (Pa) is equivalent to 1 kg/(m·s²), which helps in understanding the conversion to kilopascals (kPa). The discussion emphasizes the importance of correctly interpreting units in physics calculations.
Minh Nguyen
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Homework Statement


A mercury barometer located in a room at 25°C has a height of 750 mm. What is the atmospheric pressure in kPa?

Homework Equations


Patm = ρ*g*H0

The Attempt at a Solution


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My question pertains to the units and how it ends up as kPa in the book. I have no problem with the calculations, just the unit conversion.

ρ*g*H0 = (13580 kg/m3) * (9.81 m/s2) * [ 750 mm * (1 m/1000 mm)]

= 99914.85 kg/s2*m ... <--- is what I got.

The book got 99914.85 Pa which translates to 99.54 kPa.

Is kg/s2*m another way to say kPa?
 
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Minh Nguyen said:
Is kg/s2*m another way to say kPa
Almost. ##1\, Pa = 1\, \frac{kg}{ms^2}## See here.
 
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