Atwood Machine Lab calculations

Click For Summary
SUMMARY

The discussion focuses on calculating the acceleration due to gravity using an Atwood Machine setup with masses m1 (50g) and m2 (60g). The measured acceleration (am) was calculated as 0.00496 m/s² over a distance of 0.953m in 19.60 seconds, which is significantly lower than the expected gravitational acceleration of 9.8 m/s². The theoretical acceleration (at) was computed as 0.891 m/s² using the formula at = (m2 - m1)g / (m1 + m2). The discrepancy is attributed to potential unwanted resistance in the pulley system.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with Atwood Machine principles
  • Basic knowledge of kinematic equations
  • Ability to perform unit conversions (grams to kilograms)
NEXT STEPS
  • Review the effects of friction and resistance in pulley systems
  • Learn about the derivation of acceleration equations in Atwood Machines
  • Explore methods to minimize resistance in experimental setups
  • Investigate the impact of mass measurement accuracy on experimental results
USEFUL FOR

Physics students, lab instructors, and anyone conducting experiments involving Atwood Machines or gravitational acceleration calculations.

~christina~
Gold Member
Messages
714
Reaction score
0

Homework Statement


My results are coming out funny and I was wondering if I was doing something wrong.
I have to find acceleration due to gravity.

one of my values ...

m2 (decending mass) = 60g
m1(ascending mass)= 50g

distance traveled= 95.3cm or .953m

time traveled average= 19.60s

total mass (m1 + m2)= 110g


Homework Equations


am (measured)= 2y/t^2

at(theoretical) = (m2-m1)g/(m1 + m2)


The Attempt at a Solution



well I try to find g from the am (or measured acceleration) by using the am and plugging into the theoretical acceleration (at) equation but find g instead of a.

am= 2(.953m)/(19.60s)^2
am= 0.00496m/s^2

then plugging into the at equation..

am(m1+m2)/ (m2-m1)= g

[0.00496m/s^2 (110g)]/ 10g= 0.54m/s^2 ===> this is so not 9.8m/s^2..

Basically that's it..except I also find the theoretical acelleration from using 9.8m/s^2 which would be the ideal and find that but I get...

at= (m2-m1)g/ (m1 + m2)

at= (10g)(9.8m/s^2) / (110)= .891m/s^2 for acceration.


I'm supposed to ignore the friction..

I really don't know why it comes out like this..Am I doing anything incorrectly??
I have to get this right or explain why it went wrong since this is for a lab report.

Thank You .
 
Physics news on Phys.org
You seem to be doing the analysis correctly. I'd guess that there was some sort of unwanted resistance in the pulley system, because 19.6 seconds is a long time to travel 1 meter.
 
Oh..okay Thank Kurdt! =)
 

Similar threads

Replies
3
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 97 ·
4
Replies
97
Views
17K
  • · Replies 13 ·
Replies
13
Views
4K
Replies
1
Views
2K
Replies
9
Views
7K
Replies
1
Views
4K
Replies
16
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K