Average Angular Acceleration of a CD

AI Thread Summary
The average angular acceleration of a CD is calculated using the change in angular velocity over time. The initial angular velocity is converted from 460 rpm to approximately 48.17 rad/s, while the final velocity is converted from 202 rpm to about 21.15 rad/s. The total time for the CD's rotation is 3588 seconds. The calculated angular acceleration is -0.00753 rad/s², but the answer may not be accepted due to formatting issues in online grading systems like WileyPlus, which often require scientific notation. Proper formatting is crucial for successful submission in these systems.
kmb11132
Messages
13
Reaction score
0

Homework Statement



A CD has a playing time of 59.8 minutes. When the music starts, the CD is rotating at an angular speed of 460 revolutions per minute (rpm). At the end of the music, the CD is rotating at 202 rpm. Find the magnitude of the average angular acceleration of the CD. Express your answer in rad/s^2.

Homework Equations



angular acceleration = change in angular velocity / change in time

The Attempt at a Solution



initial angular velocity in rad/s:
460rpm / 60 * 2 * Pi = 48.17rad/s

final angular velocity in rad/s:
202rpm / 60 * 2 * Pi = 21.15rad/s

time in s:
59.8min * 60 = 3588s

angular acceleration:
(21.15 - 48.17) / 3588 = -.00753rad/s^2

I'm really not sure why this is incorrect. I feel like I'm making a really obvious/face-palm type mistake.
 
Physics news on Phys.org
I agree with your answer.

It sounds like you are submitting this for online grading. For some reason these are known to have bugs in terms of accepting answers that are slightly off or in a different format from what the accepted answer is. I am always puzzled as to why they can't get it to act right.
 
You're exactly right. I'm using the WileyPlus system and it expected scientific notation without explicitly stating so.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top