What is the Average Angular Speed of the Leaning Tower of Pisa?

AI Thread Summary
The average angular speed of the Leaning Tower of Pisa's top is calculated using the formula ωavg = Δθ/Δt. The tower's top moves south at an average rate of 1.4 mm/y, which converts to approximately 4.4394E-11 m/s. Dividing this value by the tower's height of 59 m results in an angular speed of 7.5244E-13 rad/s, but this answer is deemed incorrect. Possible errors include incorrect entry of powers of ten, issues with significant figures, or flaws in the grading algorithm. Clarification on these points is necessary to resolve the discrepancy in the calculation.
R.H.2010
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Homework Statement



The top of a tower much like the leaning bell tower at Pisa, Italy, moves toward the south at an average rate of 1.4 mm/y. The tower is 59 m tall. In radians per second, what is the average angular speed of the tower's top about its base?


Homework Equations



ωavg=Δθ/Δt


The Attempt at a Solution



I first converted 1.4 mm/y :
1.4mm/y = (1m/1000mm) × (1y/365days) × (1day/24hr) × (1hr/60min) × (1min/60sec) = 4.4394E-11
Then, I divided the above answer by 59 m : (4.4394E-11)/59m = 7.5244E-13 rad/s but this wasn't correct. Where am I making my mistake? Thank you.
 
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Looks OK to me. I assume this is a computer-graded question. I see three possibilities (a) the formula that allows the machine to calculate the correct answer is incorrect, (b) you incorrectly entered the powers of 10 or (c) there is a problem with sig figs.
 

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