Average force if jumping off a building?

Click For Summary
SUMMARY

The average force exerted by the mattresses on a 75.0-kg stuntman who jumps from a height of 25.0 m can be calculated using the formula Favg = (M vf - M vi) / t. The time taken to fall is approximately 2.258 seconds, but the relevant time for calculating the average force during deceleration on the mattresses is significantly shorter. The initial velocity (vi) just before impact must be calculated using the equation vi = √(2gh), where g is 9.81 m/s².

PREREQUISITES
  • Understanding of basic physics concepts such as force, mass, and acceleration.
  • Familiarity with kinematic equations, specifically vi = √(2gh).
  • Knowledge of average force calculations in dynamics.
  • Ability to perform unit conversions and basic algebraic manipulations.
NEXT STEPS
  • Calculate the initial velocity of the stuntman just before impact using vi = √(2gh).
  • Determine the time taken for the stuntman to come to a stop on the mattresses.
  • Use the average force formula Favg = (M vf - M vi) / t to find the average force.
  • Explore the effects of varying the height of the jump or the compression of the mattresses on the average force.
USEFUL FOR

Physics students, educators, and anyone interested in understanding dynamics and force calculations in real-world scenarios, particularly in stunt performance and safety analysis.

mga2010
Messages
1
Reaction score
0
average force if jumping off a building?

Homework Statement



A 75.0-kg stuntman jumps from a balcony and falls 25.0 m
before colliding with a pile of mattresses. If the mattresses
are compressed 1.00 m before he is brought to rest, what
is the average force exerted by the mattresses on the
stuntman?

Homework Equations



Favg=change in power/time

t=square root of (2h)/g

The Attempt at a Solution



t=√((2*25)/9.81)
t=2.258 seconds

Favg=MVf-MVi/2.258
***vf=0 so that cancels out??***
left with: MVi/2.258

***AFTER THAT I'M LOST.***
 
Physics news on Phys.org


First, calculate the speed of the stuntman just before he hits the matresses. This is your [itex]v_i[/itex]

[tex]F_{avg} = \frac {M v_f - M v_i } {t}[/tex]

is correct, but the time used here is not the 2.258 s falling, but the much shorter time for the stuntman to come to a stop in the matresses.
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
5
Views
6K
Replies
1
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
7K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 5 ·
Replies
5
Views
6K
Replies
17
Views
6K