Average induced emf in coil with turns

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SUMMARY

The average induced electromotive force (emf) in a rectangular coil with 95 turns, measuring 29.0 cm by 40.0 cm, is calculated as the coil rotates from an angle of 39.0 degrees to a position perpendicular to a magnetic field of 1.60 T over 0.120 seconds. The correct formula for average emf is given by ε = -N (ΔΦ/Δt), where ΔΦ represents the change in magnetic flux. The initial and final magnetic flux values must be determined to compute the average emf accurately. The initial calculations provided were incorrect due to misapplication of the formula.

PREREQUISITES
  • Understanding of Faraday's Law of Electromagnetic Induction
  • Knowledge of magnetic flux and its calculation
  • Familiarity with the concept of induced emf
  • Basic proficiency in trigonometry for angle calculations
NEXT STEPS
  • Calculate magnetic flux using Φ = B * A * cos(θ)
  • Learn about the relationship between magnetic field strength and induced emf
  • Explore the implications of coil turns (N) on induced emf
  • Study examples of induced emf in rotating coils in different magnetic fields
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone interested in understanding the principles of induced emf in coils and their applications in electrical engineering.

susan14
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Homework Statement


A closely wound rectangular coil of 95.0 turns has dimensions of 29.0 cm by 40.0 cm. The plane of the coil is rotated from a position where it makes an angle of 39.0 degrees with a magnetic field of 1.60 T to a position perpendicular to the field. The rotation takes 0.120 s.
What is the average emf induced in the coil?


Homework Equations





The Attempt at a Solution


ε=ΔB/Δt*(A*cos 39°)
ε=1.6/.120*(.116*cos39)
=1.20
This is the wrong answer!
 
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susan14 said:

Homework Statement


A closely wound rectangular coil of 95.0 turns has dimensions of 29.0 cm by 40.0 cm. The plane of the coil is rotated from a position where it makes an angle of 39.0 degrees with a magnetic field of 1.60 T to a position perpendicular to the field. The rotation takes 0.120 s.
What is the average emf induced in the coil?


Homework Equations





The Attempt at a Solution


ε=ΔB/Δt*(A*cos 39°)
ε=1.6/.120*(.116*cos39)
=1.20
This is the wrong answer!

Welcome to PF, susan14! :smile:


Which formula do you have for the emf?

I have:
$$\mathcal{E}=-N {d\Phi \over dt}$$
where either ##\Phi = B_{\textit{perpendicular to A}} A## or ##\Phi = B A_{\textit{perpendicular to B}}##.




The average ##\mathcal{E}## would be:
$$\mathcal{E}_{average}=-N {\Delta\Phi \over \Delta t}=-N {\Phi_t - \Phi_0 \over t - 0}$$
where ##\Phi_0## is the magnetic flux at time t=0, and ##\Phi_t## is the magnetic flux at the final time t.

What would you get for ##\Phi_0## and for ##\Phi_t##?
And what did you do with the factor N?
 

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