Average power of sinusoidal signal

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ngibson
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Homework Statement


Question: Consider the sinusoidal signal:
A*cos([tex]\omega[/tex]t + [tex]\phi[/tex])

Determine the average power

Homework Equations


This is my first real attempt in signals and I am really confused with the question...
I guess my question would be am I suppose to take the P = lim as t-> [tex]\infty[/tex] [tex]\frac{1}{t}[/tex] [tex]\int[/tex] A*cos([tex]\omega[/tex]t + [tex]\phi[/tex]) ?

The Attempt at a Solution


I have no attempted solution yet. I am really just trying to see how to start this problem and then go from there!

Please help. Thanks
 
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The average value of a function is \frac{1}{t}\int f(t) \Delta t. For sinusoidal functions, we typically average over a period.
Also, power is proportional to amplitude squared.
 
The average power of the signal x(t) is given by:

P = lim T ---> infinity * (1/T) * [ integration of x2(t) over (0 to T) with respect to t]

please ditinguish between "T" and "t". "T" is the period of the signal and "t" is the time.

If you integrate [A cos (ωt + ф)]2 over (0 to T) and take the limit as T approaches infinity you will have the answer. The result should be [A2/2]

Hint: T in the denominator will be simplified with the T in the numerator after the integration and you have no need to substitue any value instead of T.