Axis of revolution-washer/disks

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Homework Help Overview

The discussion revolves around finding the volume of a solid of revolution formed by rotating the area bounded by the curve y=x^2, the line y=0, and the vertical line x=1 about the line x=2. The problem involves the application of integration techniques, specifically the disk or washer method.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the original poster's integration attempt and suggest breaking the problem into two integrals. There is a debate about the shape of the solid and whether the washer method is appropriate. Questions arise regarding the clarity of the problem statement and the necessity of using specific methods.

Discussion Status

The discussion is ongoing, with participants providing various perspectives on how to approach the problem. Some guidance has been offered regarding the potential to simplify the integration by considering the shape of the solid, but there is no consensus on the best method to use.

Contextual Notes

There is mention of the need for a complete problem statement and the possibility of confusion regarding the use of the washer method. Participants are also exploring the implications of the axis of revolution and the shape of the solid being analyzed.

emk
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Y=x^2, y=0, x=1 ; about x=2

v=pi r^2 T

I tried 0 to 1 intg (x^3-2)^2+2^2 dx, but it wasn't right. Not sure what to do.
 
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We're not sure what you are doing, either.

Use the homework template and give a complete problem statement.
 
It may help to break that thing up into two different integrals. The thing is shaped like a circus tent. That is, a cylinder with a spire on top. The cylinder integration can be done without calculus. Then do the spire part using your books formula (the formula for volume basically) and add the two.
 
QuarkCharmer said:
It may help to break that thing up into two different integrals. The thing is shaped like a circus tent. That is, a cylinder with a spire on top. The cylinder integration can be done without calculus. Then do the spire part using your books formula (the formula for volume basically) and add the two.

I see no spire on top, just an oddly-shaped cylinder.
 
verty said:
I see no spire on top, just an oddly-shaped cylinder.
QuarkCharmer's description makes sense to me. The point of the spire is at x=2, the axis of revolution. But the washer method just seems to complicate matters. emk, were you told to use that method here?
 
haruspex said:
QuarkCharmer's description makes sense to me. The point of the spire is at x=2, the axis of revolution. But the washer method just seems to complicate matters. emk, were you told to use that method here?

Yes, either the disk or washer method.
 
Unless I am mistaken:

mwttz8.jpg

You could easily find all these intersection points, and rewrite the equation to integrate such that the integration makes more sense to you.

Hope that is helpful.
 

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