Back of envelope calculations for thurst, specific impulse, etc.

AI Thread Summary
To calculate the thrust and power needed for a spacecraft to travel 630 million kilometers in one year with a 2000 kg payload, a constant acceleration approach is suggested. The simplest method involves accelerating quickly, coasting for a year, and then decelerating, while a more energy-efficient method entails constant acceleration for six months followed by deceleration. Using the formula for distance, a constant acceleration of approximately 1.2 micro-meters per second squared requires a thrust of about 2 millinewtons. Power calculations can be derived from the thrust and distance over time, considering kinetic energy at the midpoint. These basic calculations provide a foundational understanding for spacecraft design without delving into complex orbital mechanics.
engineer23
Messages
68
Reaction score
0
"Back of envelope calculations" for thurst, specific impulse, etc.

I am working on a project that is really out of my realm of experience, so if you could give me some basics, that would be much appreciated.
How do you determine the amount of thrust, power, etc. needed to travel a distance of 630 million kilometers in space? What if the payload is 2000 kg and I want the journey to take 1 year? Don't worry about trajectories and orbital mechanics...I just want a simple calculation. The thrust calculations I am familiar with are those in which the thrust is the force necessary to overcome drag, but I'm assuming there's a more general form? How do I get the specific impulse? Power?
Suppose I'm launching from high Earth orbit as well. I guess I need escape velocity for HEO?
I really have no experience with propulsion, but I just need some ballpark figures to base a design on.
 
Last edited:
Engineering news on Phys.org
Really it all depends on the gravity, if you not near any bodies and not in orbit then it depends on how fast you want to go - and what speed you want to be doing when you get there.

Simplest case would be to accelerate the 2000kg to full speed quickly, coast for a year and then spend a similairly negligible time slowing down.
Lowest energy case would be to accelerate constantly for 6months, then turn around and decellerate at the same rate for 6 months.

s = ut + 0.5 at^2
s = 630e9 m, t = 32e6 sec
a = 2 s/ t^2 = 1.2 e-6 m/s^2
So a constant force of 2mN would do it.
 
Last edited:
Thanks!
What is the power required for the journey then? Is it just mass*acceleration*distance/time?
 
Or you could use ke at the midpoint divided by the time to midpoint.
 
Hi all, I have a question. So from the derivation of the Isentropic process relationship PV^gamma = constant, there is a step dW = PdV, which can only be said for quasi-equilibrium (or reversible) processes. As such I believe PV^gamma = constant (and the family of equations) should not be applicable to just adiabatic processes? Ie, it should be applicable only for adiabatic + reversible = isentropic processes? However, I've seen couple of online notes/books, and...
Thread 'How can I find the cleanout for my building drain?'
I am a long distance truck driver, but I recently completed a plumbing program with Stratford Career Institute. In the chapter of my textbook Repairing DWV Systems, the author says that if there is a clog in the building drain, one can clear out the clog by using a snake augur or maybe some other type of tool into the cleanout for the building drain. The author said that the cleanout for the building drain is usually near the stack. I live in a duplex townhouse. Just out of curiosity, I...
I have an engine that uses a dry sump oiling system. The oil collection pan has three AN fittings to use for scavenging. Two of the fittings are approximately on the same level, the third is about 1/2 to 3/4 inch higher than the other two. The system ran for years with no problem using a three stage pump (one pressure and two scavenge stages). The two scavenge stages were connected at times to any two of the three AN fittings on the tank. Recently I tried an upgrade to a four stage pump...
Back
Top