Balancing Chemical Equations: How Much HCl is Consumed By 3.54 Mol of Mg?

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The discussion centers on calculating the mass of hydrochloric acid (HCl) consumed when 3.54 moles of magnesium (Mg) react according to the unbalanced equation Mg + HCl → MgCl2 + H2. Participants confirm that the equation must be balanced before performing calculations. The correct balanced equation is Mg + 2 HCl → MgCl2 + H2, indicating that 2 moles of HCl are required for each mole of Mg. The calculation reveals that 3.54 moles of Mg would consume 7.08 moles of HCl, which translates to approximately 255.24 grams of HCl. The initial answer of 10.6 grams is incorrect, highlighting the importance of proper balancing in stoichiometric calculations.
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help with this chem question please!

Homework Statement




One reaction that produces hydrogen gas can
be represented by the unbalanced chemical
equation:

Mg(s) + HCl(aq) --> MgCl2(aq) + H2(g)

What mass of HCl is consumed by the reac-
tion of 3.54 mol of magnesium? Answer in
units of g.

is the answer 10.6 g?
 
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Did you balance the equation?
 
yes i did

i know the equation i posted is unbalanced, but when i did the calculation i balanced it first.
 
So show us how you did it...
 
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