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Ball and ramp question

  1. Feb 4, 2007 #1
    1. The problem statement, all variables and given/known data
    A ball of mass 522 g starts at rest and slides down a frictionless track. It leaves the track horizontally, striking the ground.
    a. at what height above the ground does the ball start to move?

    2. Relevant equations
    I have:
    mgh=mgh_2+1/2mv^2
    which simplifies to:
    h=h_2+1/2mv^2

    3. The attempt at a solution
    I got:
    .2+1.25=1.45

    I think that 1.45 is right, but I'm a little confused on how I got to that point.:confused: Any help is most appreciated. Thanks.
     
  2. jcsd
  3. Feb 4, 2007 #2
    uhhhh,
    I think the problem probably gave a little more information then that.
     
  4. Feb 4, 2007 #3
    Oh, so sorry, it did. There was the variable h that was the height of top of ramp to ground. then there was height from bottom of ramp to ground which was 1.25 meters and then distance the ball fell from ramp in x direction which was 1 meter.
     
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