- #1

Brittbrit22

- 2

- 0

I am really confused as to

**where am I supposed to plug the value of the SLOPE in this equation:**

change in y=-1/2g(t)^2 >>>> yf-yi=-1/2g(t2-t1)^2

change in y=-1/2g(t)^2 >>>> yf-yi=-1/2g(t2-t1)^2

I also don't understand why I wrote down y=mx+o -- something about velocity being zero

I know it's really simple but for some reason I am just not getting it.

This isn't really homework, it's a lab calculation. I apologize if this question classifies as a

"homework question"