- #1
graustet
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Homework Statement
A 4.80 -kg ball is dropped from a height of 10.5 m above one end of a uniform bar that pivots at its center. The bar has mass 8.00 kg and is 4.00 m in length. At the other end of the bar sits another 5.10 -kg ball, unattached to the bar. The dropped ball sticks to the bar after the collision.
how high will the other ball go after the collision??
Homework Equations
Im assuming a change in kinetic/potential energy, moment of inertia, conservation of momentum
The Attempt at a Solution
i found the potential energy of the first ball and used that to find the speed of the ball before it hits the rod. using the conservation of momentum of a inelastic equation i found the resulting speed of the rod and first ball. using that speed i applied it to the rod and other ball to find its kinetic energy. then i set the kinetic energy equal to the potential to find the height. i got like 10.3 meters. i know that's not the answer because by reasoning i thin kt hat the answer should be around 1 meter or so.
… this is a turny thingy …