Ball performing small oscillations within a hollow cylinder

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SUMMARY

The discussion focuses on calculating the angular frequency of a small ball oscillating within a hollow cylinder, emphasizing the conditions of rolling without slipping. The total kinetic energy (T) is derived from both translational and rotational components, expressed as T = (1/2)m[(R−r)²\dot{ϕ}²] + (1/2)I\dot{ϕ}², while the potential energy (V) is given by V = mgy. The Lagrangian (L) is formulated as L = T - V, leading to the determination of angular frequency through the Euler-Lagrange formalism. Participants clarify the implications of rolling without slipping and the relationship between angular velocity and the center of mass velocity.

PREREQUISITES
  • Understanding of Lagrangian mechanics
  • Familiarity with rotational dynamics and moment of inertia
  • Knowledge of potential and kinetic energy concepts
  • Concept of rolling without slipping in mechanics
NEXT STEPS
  • Study the Euler-Lagrange equation in detail
  • Learn about the implications of rolling without slipping in mechanical systems
  • Explore the relationship between angular velocity and linear velocity in rolling objects
  • Investigate the effects of friction on motion in cylindrical systems
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Students and educators in physics, particularly those focusing on classical mechanics, as well as engineers dealing with rotational dynamics and oscillatory motion.

  • #31
I am not sure why only the second term counts/is used. I could make an educated guess, or try to at least. Is it because around the point of stable equilibrium the first derivative is zero as the potential obtains its minimum and the first term is subtracted from the potential to obtain the "effective" potential? Am I close?
The second part of that problem, with the hollow cylinder and the ball, asks for the angular frequency of the small oscillations supposing that this time the ball slips and doesn't roll.
 
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  • #32
peripatein said:
I am not sure why only the second term counts/is used. I could make an educated guess, or try to at least. Is it because around the point of stable equilibrium the first derivative is zero as the potential obtains its minimum and the first term is subtracted from the potential to obtain the "effective" potential? Am I close?

This is not just close, this is exactly it.

The second part of that problem, with the hollow cylinder and the ball, asks for the angular frequency of the small oscillations supposing that this time the ball slips and doesn't roll.

If the problem says "does not roll", then there no kinetic energy due to rolling. Even though I am not sure how one could achieve that in practice.
 
  • #33
It says "slips without rolling". Does that mean that I am solely left with the translational kinetic energy whereas the rotational equals zero, and all my expressions remain the same?
 
  • #34
I believe this is what is meant. But, as I said, I do not like this. Even if there is no friction, a freely moving ball will still rotate inside a cylinder. This is seen from considering the torques due to the weight of the cylinder and due to the normal force. I would bring this up to to your professor.
 

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