Ball thrown striaght up part C

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To solve the problem of two balls being thrown and dropped from a building, one must derive equations for the height of each ball over time, using different variable names for clarity. The first ball's motion is influenced by its initial velocity and the acceleration due to gravity, while the second ball, dropped one second later, only experiences gravitational acceleration. The key is to establish a relationship between the heights of both balls at the time they hit the ground, leading to the conclusion that if the initial velocity exceeds a certain threshold (vmax), simultaneous ground impact is impossible. The discussion emphasizes the importance of correctly setting up the equations and understanding the timing of each ball's motion. Ultimately, finding vmax involves analyzing these equations to determine the conditions for simultaneous impact.
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Homework Statement


A ball is thrown straight up from the edge of the roof of a building. A second ball is dropped from the roof 1 second later. You may ignore air resistance

If vo is greater than some value vmax, a value of h does not exist that allows both balls to hit the gorund at the same time. Solve for vmax.

Homework Equations



y=yo+vo*t+1/2*a*t^(2)

The Attempt at a Solution



I am not sure how to start it. Can somebody give me some hints?
 
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Presumably h is the height of the roof. Write down equations, one for each ball, for the height of the ball at time t. Make sure to use different variable names as appropriate (not making them both just 'y'). Using those equations, write the statement that each is on the ground at some time tg.
 
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