Ball throws upward, find maximum height

AI Thread Summary
To find the maximum height of a ball thrown upward with an initial velocity of 10 m/s, one can use the principle of energy conservation, where the initial kinetic energy converts to gravitational potential energy. The maximum height is reached when the vertical velocity (vy) becomes zero. The mass of the ball is irrelevant in this calculation because the gravitational force acts equally on all objects, allowing for the use of the formula h = (vi^2) / (2g), where g is the acceleration due to gravity. Substituting the values, the maximum height can be calculated without needing the mass. Understanding these principles clarifies the relationship between kinetic and potential energy in projectile motion.
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Homework Statement


You throw a ball directly upward giving the ball an initial velocity of 10m/s. Neglecting friction, what would be the maximum height of the ball? (Explain why you do not need to know the mass of the ball)


Homework Equations


not sure


The Attempt at a Solution


vi=10m/s d=?
not much of an attempt, i know
 
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The ball has an initial kinetic energy, which is transformed into an increase in gravitational potential energy.

Max height occurs when vy equals zero.
 
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so if v1 = 10 m/s , think wut would the speed be at maximum height , and remember there is always the acceleration of gravity [ down ] acting on all object thrown upward!
 
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