Bare potential energy equation

AI Thread Summary
The discussion revolves around the confusion regarding the bare potential energy equation and its implications for calculating the mass of an electron. The user attempts various integration methods to derive potential energy but encounters an issue where the calculation suggests that an electron's charge is effectively doubled in the context of self-interaction. This leads to the question of why the potential energy appears to account for the electron's charge twice, despite there being only one charge present. The user seeks clarification on the physical interpretation of these results, particularly in relation to the behavior of charged spheres and their resistance to changes in radius. The inquiry highlights a fundamental misunderstanding of charge interactions in potential energy calculations.
Zaphodx57x
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I am having a problem understanding this problem which references this exercise .

I tried it a couple different ways. I used
\begin{multline*}<br /> \Delta U(Potential Energy) = Uf - Ui = Uf - U(r = infinity) = Uf - 0 \\<br /> dU = Uf = -W = \int F * ds = \int E * Q * ds \\<br /> Uf = -\int E * Q * dr = -\int \frac{kqQ}{r^2} = \frac{kqQ}{r}<br /> \end{multline*}
I also tried using the bare potential energy equation and using two arbitrary surface areas (dA) on opposite sides of the sphere with a distance between charges of 2r , then integrating each over just half of the sphere, which provided the same result.
The problem I have is that this result gives me a pretty decent result for the mass of an electron if I assume that q = Q = charge of an electron. But this assumption seems to say that the electron is pushing against itself by its full charge.
That is a force \frac{QQ}{r^2} is present instead of a \frac {(Q)(q}{r^2} where q = \frac {Q}{n} or some other fractional or modified charge.
This almost makes sense to me in that if a sphere were to have a charge spread evenly over its surface and its radius is infinity, it still acts as if it has all its charge at its center and therefore would resist a decreasing radius of like charge.

If anyone can find a way to explain why this problem makes sense I would really appreciate it. I just don't understand how the Potential energy can contain the electron's charge twice, when there is only one charge to begin with.
 
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Oops, I posted this in the wrong place, i'll repost in the homework section.
 
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