Barometer reading in an elevator .

AI Thread Summary
When a barometer is in a stationary elevator, it reads 76 cm. As the elevator accelerates upward, the effective gravitational acceleration increases, leading to a decrease in the barometer reading. The pressure at the mercury surface remains equal to atmospheric pressure, which is constant, but the increased effective gravity causes a lower height of mercury in the tube. Therefore, the correct answer to the homework question is that the reading will decrease. Understanding the relationship between effective gravity and pressure is key to solving this problem.
Abhishekdas
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Barometer reading in an elevator...

Homework Statement


A barometer kept in an elevator reads 76cm when it is at rest. If the elevator goes up with increasing speed , the reading will (a).increase (b)decrease (c)remain constant (d) become zero...



Homework Equations





The Attempt at a Solution


Dont have any clue...can anyone give me a start?
 
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consider the change in total acceleration. if it is a upwards, then net accn = g + a
 


Ya i know that is the g effective you are talking about...But what to do...with that...Do i apply Bernoulli's theorem at the top of the of the mercury surface in the tube and at the surface open to atmosphere?
 


just use rho(g-effective)h
 


Can you give me a better explanation...?
 


the atmos pressure is hXrhoXg(effective). the measurement is h, like "the pressure is 76cm". now if g effective is greater than g actual, h would have a less value for same pressure, and vice-versa.
 


Hi bjd40@hotmail.com...
So you mean to say that the pressure at the surface of mercury in beaker is same (equal to atmospheric pressure which is constant close to the earth)...SInce it is also = h*rho*geff as geff has become 'g+a' ie increased the 'h' has to decrease...Is that it?
 
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