Basic Algebra Simplifying a complex fraction

[Femme_physics]

This problem comes from an engineering exercise (hence the C/R which you can ignore). I want to see if I got it right.

http://img51.imageshack.us/img51/3989/mama1h.jpg

http://img851.imageshack.us/img851/3401/mam2.jpg

 

[JHamm]

Just to clarify
$$C = \frac{62.5}{(x+3)(x+4)}$$
and
$$R = 1 + \frac{0.625}{(x+3)(x+4)} + \frac{7}{(x+3)}$$

?

 

[Femme_physics]

Just to clarify
$$C = \frac{62.5}{(x+3)(x+4)}$$
and
$$R = 1 + \frac{0.625}{(x+3)(x+4)} + \frac{7}{(x+3)}$$

?

I don't know, I only know what I'm trying to solve not other suppositions

 

[HallsofIvy]

Then I guess the question is: what are you trying to do?

 

[micromass]

In the last line, I don't really see why you don't simplify by eliminating (x+3)(x+4).

 

[I like Serena]

How does the smiley factor in?



Btw, it looks right, but it would be nice if you wrote things down a bit neater.
And you can simplify it further as micro suggested.

 

[Femme_physics]

Then I guess the question is: what are you trying to do?

Well, I just have a engineering transfer (C/R) function that I'm looking to simplify. as per title .

The question is "am I right so far?" , basically. Just checking I didn't do a math error.

In the last line, I don't really see why you don't simplify by eliminating (x+3)(x+4).

True! I did, and went on to simplify ...
http://img39.imageshack.us/img39/1011/cr2b.jpg

Can I simplifiy it even more?

How does the smiley factor in?

Smilies are an intensively complex algorithmic field of math. I don't even want to get into it. Plus, somehow all my results to that end up in a frowny face :(

You can consider this smiley as a stray. Deviating from another exercise. Sneaky little bastard..

 

[technician]

Can't you just multiply out the brackets under the division line to get
X^2 + 14x + 40.625 as the denominator

 

[Femme_physics]

Can't you just multiply out the brackets under the division line to get
X^2 + 14x + 40.625 as the denominator

Thing is I'm not sure if I'll consider having a power of 2 in my equation all that simplified?

 

[I like Serena]

Smilies are an intensively complex algorithmic field of math. I don't even want to get into it. Plus, somehow all my results to that end up in a frowny face :(

You can consider this smiley as a stray. Deviating from another exercise. Sneaky little bastard..

 

[Femme_physics]

rofl!

 

[SammyS]

This problem comes from an engineering exercise (hence the C/R which you can ignore). I want to see if I got it right.

http://img51.imageshack.us/img51/3989/mama1h.jpg

I hate to butt in, because I know that you and I like Serena have developed a rapport .

What is the expression you are starting with?

Is it :

$\displaystyle\frac{C}{R}=\frac{\displaystyle\frac{62.5}{(x+3)(x+4)}}{\displaystyle 1 + \frac{0.625}{(x+3)(x+4)} + \frac{7}{(x+3)}}\ \ ?$​

 

[Femme_physics]

I hate to butt in, because I know that you and I like Serena have developed a rapport .

Haha ;) They've been noticing us, ILS!

Just don't tell them we met IRL eh? ;)

What is the expression you are starting with?

I'll go the whole mile with the original question (S replaces X):

http://img841.imageshack.us/img841/8366/ex1ta.jpg

http://img849.imageshack.us/img849/4486/ex2l.jpg

 

[SammyS]

That result looks right, with or without the smiley.

 

[Femme_physics]

Thanks!