It IS the correct section. You initially posted it in the Precalculus section. I moved it.emergentecon said:1. Given the elementary nature of the question, why is Calculus & Beyond Homework not the correct section?
You can post the corrected question here in this thread.emergentecon said:2. It is not a function of deleting an answered question. I misunderstood something I was reading, and thereby posted an erroneous question.
Once I realized my error, I no longer had a problem with the question.Mark44 said:It IS the correct section. You initially posted it in the Precalculus section. I moved it.
You can post the corrected question here in this thread.
The formula for calculating partial derivatives of x^2 + y^2 < 1 is as follows:
∂/∂x(x^2 + y^2) = 2x
∂/∂y(x^2 + y^2) = 2y
The purpose of calculating partial derivatives of x^2 + y^2 < 1 is to find the rate of change of the function in the x and y directions. This can be useful in determining the direction in which the function is increasing or decreasing, as well as finding critical points and determining the shape of the function.
The partial derivative of x^2 + y^2 < 1 can be interpreted geometrically as the slope of the tangent line to the function at a specific point (x,y) on the graph. It represents how the function is changing in the x and y directions at that point.
Yes, partial derivatives of x^2 + y^2 < 1 can be negative. This indicates that the function is decreasing in that direction at a specific point on the graph.
Yes, calculating partial derivatives of x^2 + y^2 < 1 has many real-world applications, particularly in physics, engineering, and economics. For example, in physics, partial derivatives are used to calculate the velocity and acceleration of moving objects. In economics, they are used to analyze the relationships between variables in economic models.