1. The problem statement, all variables and given/known data A soccer ball is kicked with an inital speed of 12.0 m/s in a direction of 25.0 degrees above the horizontal. Find the magnitude and direction of its velocity A) 0.250 s and b) 0.500 s after being kicked. C) Is the ball at its greatest height before or after 0.500 s? 2. Relevant equations a = (Vf - Vi)/t d = ((Vi + Vff / 2)t d = Vit + 0.5at[super]2[/super] Vf = 2ad + Vi[super]2[/super] 3. The attempt at a solution I'm really stuck on this. I've gone with: Vh = cos(25)12.0m/s Vh = 10.88 m/s Vi = sin(25)12.0m/s Vi = 5.07 m/s Now I've heard that in class if your initial vertical velocity in these types of problems has to be equal to the final or finishing vertical velocity... So since I have Vi = 5.07 m/s ; I set Vf = -5.07 m/s ...and worked from there, but I am not sure at all if this was correct. From there I tried to work out the displacement ... Vf = 2ad + Vi[super]2[/super] -5.07m/s = 2(-9.8m/s2)(d) + 5.07[super]2[/super] d = 1.57 m ... and this is where I KNEW (at least I think I know...) that I'm horribly wrong. A kick with an initial vertical velocity of 5.07 m/s and overall 12.0 m/s ... and my displacement is 1.57 m total... If anybody can help get me pointed in the right direction on this ... I would GREATLY appreciate it.