Basic Relativity Question (Time Dilation)

AI Thread Summary
The discussion revolves around a basic relativity question concerning time dilation and distance perception for a spaceship traveling to Proxima Centauri at 0.24c. The pilot's perspective would yield a different time measurement than that of a stationary observer on Earth due to time dilation effects. The participant questions whether time dilation applies only to stationary observers and if the distance remains 4.2 light years for those aboard the spaceship. Clarification is provided that while the pilot experiences time differently, the perceived distance is not the same as that measured from Earth. Ultimately, the conversation highlights the complexities of relativity in understanding time and distance from different frames of reference.
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Homework Statement



Proxima Centauri, the star nearest our own, is some 4.2 ly away. (a) If a spaceship could travel at a speed of 0.24c, how long would it take to reach the star according to the spaceship's pilot? (b) What would someone in the frame that moves along with the spaceship measure as the distance to Proxima Centauri?


Homework Equations



d = v/t
t' = t/sqrt(1-(v/c)^2)


The Attempt at a Solution



I know this question is probably very basic, but I'm having a hard time trying to see reason in the way that the question is asked. If the pilot is moving in the frame of reference of the spaceship, would not the time taken to reach the star just be (v/d)? Wouldn't time only be dilated for a stationary observer?

As for part (b), would not a person moving along with the spaceship's frame of reference perceive the same time? Wouldn't this imply that the perceived distance is still 4.2 ly?
 
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I know this question is probably very basic, but I'm having a hard time trying to see reason in the way that the question is asked. If the pilot is moving in the frame of reference of the spaceship, would not the time taken to reach the star just be (v/d)? Wouldn't time only be dilated for a stationary observer?
v/d, where d is calculated in the system of the spaceship. This is not 4.2 light years.

As for part (b), would not a person moving along with the spaceship's frame of reference perceive the same time?
The same time as the spaceship, but not the same time as we on earth.
 
That cleared things right up! Thanks!
 
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