Basketball hang time and the acceleration of gravity

[david12]

Here is my question guys ...i guess you can help me out .

1.A basketball player achieves a hang time of 1.33 second in dunking the ball.the acceleration of gravity is 9.8m/s^2.what is vertical hight will he attain.answer in m.

here is what i did.

Y=Y(inital) + v(inital)t + 1/2 gt^2

which is Y = 0.5(9.8)(1.33^2)
=8.6676 m

I don't know what i did wrong but my answer is wrong.

thank you.

 

[LowlyPion]

Here is my question guys ...i guess you can help me out .

1.A basketball player achieves a hang time of 1.33 second in dunking the ball.the acceleration of gravity is 9.8m/s^2.what is vertical hight will he attain.answer in m.

here is what i did.

Y=Y(inital) + v(inital)t + 1/2 gt^2

which is Y = 0.5(9.8)(1.33^2)
=8.6676 m

I don't know what i did wrong but my answer is wrong.

thank you.

Hang time is total time in the air isn't it? Half of that should give you time to maximum height.