Battery & Resistance: Why is There a Difference?

AI Thread Summary
The discussion centers on the differing resistance measurements of a 1.5V alkaline battery and a mV power supply, with the battery showing significantly higher resistance. The confusion arises from the measurement techniques used, as a digital multimeter (DMM) is not suitable for measuring the output resistance of active voltage sources. Instead, it is suggested to use a method involving simultaneous voltage and current measurements with different resistors to accurately determine source resistance. The conversation also touches on the principles of how ohmmeters function, emphasizing the importance of understanding the measurement process. Ultimately, the differences in resistance are attributed to the nature of the voltage sources and their impedance characteristics.
ttsky
Messages
20
Reaction score
0
Hi every one,

I placed a multimeter probe across the terminals of a 1.5 v alkaline battery and saw 2 M Ohms, I did the same across a mV power supply at 1.5 volts and got little below 1.5 K ohms. I don't understand what makes them have diffrent resistance, and exactly why?

I did this because I had an odd situation with a SIL 2 (safty integrity level) rated gas analyser, the analyser would only work with a real sensor or a battery at correct voltage, but not a simulator (e.g mV supply).The diffrence as it seems is the sensor has very high impedance. So i measured the resistance of the battery and the supply, and now i am confused why the battery shows such high resistance.
 
Engineering news on Phys.org
ttsky said:
Hi every one,

I placed a multimeter probe across the terminals of a 1.5 v alkaline battery and saw 2 M Ohms, I did the same across a mV power supply at 1.5 volts and got little below 1.5 K ohms. I don't understand what makes them have diffrent resistance, and exactly why?

I did this because I had an odd situation with a SIL 2 (safty integrity level) rated gas analyser, the analyser would only work with a real sensor or a battery at correct voltage, but not a simulator (e.g mV supply).The diffrence as it seems is the sensor has very high impedance. So i measured the resistance of the battery and the supply, and now i am confused why the battery shows such high resistance.

That's not how you measure the output resistance of a voltage source. The DMM resistance measurement is for passive devices, not for active sources of voltage or current.

Instead, make 2 output voltage and current measurements using 2 different resistors, and solve the 2 simultaneous equations for the source resistance of the voltage source. Are you familiar with that measurement technique?
 
ttsky: You might want to read up on how an ohmmeter works.
http://en.wikipedia.org/wiki/Ohmmeter

A more accurate type of ohmmeter has an electronic circuit that passes a constant current (I) through the resistance, and another circuit that measures the voltage (V) across the resistance. According to the following equation, derived from Ohm's Law, the value of the resistance (R) is given by: R= V/I
 
Thread 'Weird near-field phenomenon I get in my EM simulation'
I recently made a basic simulation of wire antennas and I am not sure if the near field in my simulation is modeled correctly. One of the things that worry me is the fact that sometimes I see in my simulation "movements" in the near field that seems to be faster than the speed of wave propagation I defined (the speed of light in the simulation). Specifically I see "nodes" of low amplitude in the E field that are quickly "emitted" from the antenna and then slow down as they approach the far...
Hello dear reader, a brief introduction: Some 4 years ago someone started developing health related issues, apparently due to exposure to RF & ELF related frequencies and/or fields (Magnetic). This is currently becoming known as EHS. (Electromagnetic hypersensitivity is a claimed sensitivity to electromagnetic fields, to which adverse symptoms are attributed.) She experiences a deep burning sensation throughout her entire body, leaving her in pain and exhausted after a pulse has occurred...
Back
Top