Find Optimal Distance from Wall for Max Angle of Vision

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To determine the optimal distance from the wall for maximizing the angle of vision, the observer's eye level and the height of the picture must be considered. The equation tan(θ + β) = (1.4 + 1.8)/x is suggested for calculating the angle, but it requires clarification on the definitions of the angles involved. Visualizing the scenario with a diagram can aid in understanding the geometry of the situation. The discussion emphasizes the importance of accurately defining the angle of vision to solve the problem effectively. A clear representation and correct application of trigonometric principles are essential for finding the solution.
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A picture 1.4 meters high stands on a wall so that its lower edge is 1.8 meters above the eye of an observer. What is the most favorable distance from the wall for this observer to stand (that is, to maximize his or her angle of vision)?

I've tried using the tan (pheta+beta) = (1.4+1.8)/x equation
but it still doesn't work out...
 
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Draw a picture first! What is "angle of vision"? Show it in the picture!

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