Beam Deflection Problem: Determining Slope and Deflection at a Point x on a Beam

AI Thread Summary
The discussion centers on solving a beam deflection problem using the bending stiffness equation, where the goal is to determine the slope and deflection at a specific point on the beam. The user has calculated the reactions at the supports and derived expressions for deflection and slope using Macaulay brackets. However, confusion arises when attempting to simplify the integration constant "A," which consistently results in a complicated fraction. A suggestion is made to verify the expression for "A" by testing a specific case where a equals b, which could indicate whether the derived formula is correct. The user seeks clarification on their approach to achieve the expected final answers for slope and deflection.
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Homework Statement



Determine the slope and deflection at the point x on the beam (attached image)


Homework Equations



Bending stiffness equation: EIV'' = M
where E = young's modulus, I = second moment of area, V = deflection, M = moment



The Attempt at a Solution



By taking moments about both supports I have determined the reactions at the left and right supports to be b/(a+b) and a/(a+b) respectively.

Cutting the beam between point x and the right hand support:

EIV'' = M = bx/(a+b) - <x-a> (where <> are macaulay brackets)

EIV' = bx^2/2(a+b) - (<x-a>^2)/2 + A

EIV = bx^3/6(a+b) - (<x-a>^3)/6 + Ax + B

Here's where I get confused:

Using V=0 at the boundary conditions (x=0 and x=a+b) to find the integration constants, B is found to be 0 but A always comes out as a complicated fraction that I can't seem to simplify to get anything sensible.

I know the final answers are supposed to be: V' = (ab/3)((a-b)/(a+b))
and V =-a^2b^2/3(a+b)


I have worked through the question several times and I can't figure out where I'm going wrong so any help would be much appreciated.
 

Attachments

  • beamQ.GIF
    beamQ.GIF
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Have you checked your complicated expression for "A" by putting a=b and setting the gradient to zero at the centre? It is no guarantee if it is correct, but, if it is incorrect in this special case, then it will be incorrect more generally.
 
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