mn4j said:
You did not define what you mean by classical physics.
That's easy: let's just say, that by classical physics in this case I mean all physics known before 1920. To make this comment self-contained, I repeat my claim: in classical physics Bell's technical assumption (that you and Jaynes and de Raedt keep saying is unjustified) is always true. You disagree. Well, it seems that to refute my claim one example would suffice. This example must be of the following (just to spell it out): two space-like separated experiments are done and the result of Alice's experiment "A" is NOT statistically independent from Bob's choice of experimental setup "b" or his outcome "B".
Maybe I miss something here, but I don't see how your harmonic oscillators can provide a counterexample to that. Please explain, if you think it can. And here's another consideration: if it were THAT easy to provide a counterexample to Bell (by just taking two harmonic oscillators), then why would all this story about deterministic learning machines be necessary? It seems to me that you make an oversimplification here. It's impossible to replicate QM correlations by just considering two oscillators or clocks, is it?
I take it you do not understand the difference between logical dependence and physical causation.
Just a short note: I think I do. It also seems to me that "logical dependence" is a term that you took from Jaynes (and de Raedt), because it's never being used in modern probability/statistics treatments. The precisely defined term that is usually used is "statistical dependence". Try googling this term, and your one. "Logical dependence" is used only in mathematical logic, but that's different.
You seem to have stuck on this one loophole and you can't get passed it.
Well, I'm sorry, but I believe that this is the most important and crucial point here.
You did not tell me if you believe the QM formalism also suffers from the coincidence time loop-hole. I wonder why?
Because I don't understand what your question means! How can a "formalism" suffer from a "loophole"? I think that this question gives another indication that you fail to understand the meaning of this loophole issue.
Let me give an analogy (it will be a rather silly one). Imagine we're trying to prove general relativity by observing gravitational waves. The opposing theory is Newtonian gravity, where there's no waves. So it the waves are observed, Newtonian theory is proved to be false. The experiment is done and experimental setup for some reason has to be located on the surface of the ocean. The gravitational waves are indeed observed. It may seem that GR is proven, but there's a subtlety: the whole apparatus was located in water and there were waves in water, so in principle it's possible to explain the apparent gravitational waves that were observed by just some influence from the water waves. So folks that don't believe in GR take this view. This experimental problem is called "water loophole" and experimenters are working hard to avoid it putting the setup on a hard ground, but they didn't succeed so far.
To spell it out: GR corresponds to QM, gravitational waves to the violation of Bell's inequalities, water loophole to coincidence-time loophole, explanation of how this faulty experiment can result in apparent detection of gravitational waves to de Raedt's explanation of how the faulty experiments can result in apparent violation of Bell's inequalities.
And now you come and ask, whether "the QM formalism also suffers from the coincidence time loop-hole". Analogy: does the general relativity suffer from the water loophole? This question just doesn't make any sense to me.
I have read every article I point you to. Have you read the ones you point me to? Did you bother reading de Raedt's reply? What exactly do you believe misses the point. Spell it out and I will explain why it is you who missed the point. We can go into technical detail if you prefer.
OK, I'm sorry for suspecting that you didn't read them. Yes, I also did. We could go into technical details, but it doesn't make any sense before we understand the issue of loophole in a similar way. Actually, when I read de Raedt's reply I was just lost several times. I think it misses the point, because it's unclear, and it is unclear because de Raedt apparently also does not understand this loophole issue. It's just that his reply doesn't really reply to what was said by Seevinck and Larsson. The critique is almost one page long and makes a clear point, while de Raedt writes a lengthy reply with all kind of beating around the bush.
Here's one particular example (maybe it's not the most important one. I don't remember any more, but I just have this written down anyway). Seevinck and Larsson say that in de Raedt's model \gamma is less then \gamma_0 which would be necessary to violate the inequality modified to take a loophole into account (and this equality is still violated by QM). de Raedt triumphally replies that they made a mistake in derivation, and then presents his own version of this derivation, which results in \gamma -> 0. Zero is clearly still less than \gamma_0, but he never comments on it.
The answer is so blindingly obvious I did not expect that you were serious. De Raedt gave you the answer even. The pattern gets smeared! <...> That is a very naive look at the situation. You can't be serious?
Oh, now I see that that's just a misunderstanding. Probably I didn't explain my experiment well enough, and now I checked and found that it's not described in arXiv version of the paper (
http://arxiv.org/abs/0809.0616). It's just that when I asked de Raedt about this paper, he sent me a draft with a fuller version, and the experiment is described there. We're just talking about different experiments. You're right about yours, that's clear (and that "experiment" really is stupid and obvious, I agree).
Roughly speaking, what I meant is that screen is jittered, detection events are counted in individual detectors and then relocated with a computer program, that takes into account where the screen was at the moment of detection. Does it make more sense now? The crucial point is that de Raedt's detectors have first to learn before they start reproducing QM probabilities, and by jittering we prevent them from learning correctly (I quote de Raedt: "In other words, the experiment should address a time scale that is sufficiently short such that our detector models have not yet reached the stationary state").
He actually proposes a bit different setup, where only *single* detector is used, and it's slided back and forth along the "screen" line. The detection events are counted and then plotted versus the position of the detector at the moment of detection. If this detector is moved slowly (so that it reaches stationary state at every point) then the resulting plot will show the usual interference pattern. However if it's moved fast, then it would get smeared. Not because of this silly "moving camera" effect, but because detector doesn't have time to learn afresh at every single point.
Please tell me if this experiment now makes sense to you. If it does, then my questions remain the same. Do you think that interference pattern will change? What do you think is the prediction of the usual QM? What would you say if it actually doesn't change?
I can point to umpteen questions of mine you have not answered but then again I'm not keeping score. Are you ready to concede that classical systems DO learn just like in de Raedt's model? Are you ready to concede that Bell's model does not account for systems which learn, like de Raedt's?
First question: well, in the certain sense, yes. If the billiard ball getting kicked by another billiard ball counts for "learning", then yes. It's just that nobody in the times of classical physics would think that parts of the screen "learn" the phase of the incoming photons.
Second question: no, not yet. As I already said, here I should take a better look on the Popescu article. I didn't have time so far.