(adsbygoogle = window.adsbygoogle || []).push({}); Bernoulli -- Find the general solution

1. The problem statement, all variables and given/known data

Find the general solution of:

y'+xy=xy^3

2. Relevant equations

Bernoulli's Equation

3. The attempt at a solution

y'+xy=xy^3

(y^-3)y'+x(y^-2)=x

Let v=(y^-2), thus v'=((-2y^-3)y'

Then,

-v'/2+xv=x

Multiply through by (-2)

v'-2xv=-2x

Now it's in first-order linear so I multiply by e^int(-2x)dx = e^(-x^2)

(e^(-x^2))v'-2xe^(-x^2)=2xe^(-x^2)

This is where I'm getting stuck :(

BECAUSE: the integral of e^(-x^2) is the "error function?"

According to Wolfram, integral e^(-x^2) dx = 1/2 sqrt(pi) erf(x)+constant

----

Anyone get anything different or know where I might have messed up?

THANK YOU!!

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# Homework Help: Bernoulli - Find the general solution

**Physics Forums | Science Articles, Homework Help, Discussion**