Beta decay of deuterium and triterium

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SUMMARY

Deuterium cannot undergo beta decay due to its stability as an isotope of hydrogen, which prevents it from decaying into a different nucleus. In contrast, tritium can undergo beta decay, converting a neutron into a proton and resulting in helium-3 (He-3). The discussion highlights the importance of energy balance in nuclear reactions and the implications of resulting products on stability. Additionally, it notes that beta decay can occur in two forms, affecting the neutron and proton count in the resulting nucleus.

PREREQUISITES
  • Understanding of nuclear stability and isotopes
  • Knowledge of beta decay processes
  • Familiarity with nuclear reactions and energy balance
  • Basic concepts of particle physics
NEXT STEPS
  • Research the principles of nuclear stability and the factors affecting it
  • Learn about the different types of beta decay and their implications
  • Investigate the energy balance in nuclear reactions
  • Explore the properties and applications of helium-3 in nuclear physics
USEFUL FOR

Students of nuclear physics, educators explaining isotopic stability, and researchers interested in nuclear decay processes.

pbonnie
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Homework Statement


Explain why deuterium cannot undergo beta decay or produce a stable nucleus, while tritium can.


Homework Equations


n/a


The Attempt at a Solution


There was nothing in the lesson that really explained this, and the only reason I can find online is because deuterium is a stable isotope of hydrogen so it does not decay. I'm guessing that there is more to this, but I'm not sure what that would be.
 
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Consider what the resulting nucleus could consist of. Tritium can convert N->P making He-3.
 
pbonnie said:

Homework Statement


Explain why deuterium cannot undergo beta decay or produce a stable nucleus, while tritium can.

The Attempt at a Solution


There was nothing in the lesson that really explained this, and the only reason I can find online is because deuterium is a stable isotope of hydrogen so it does not decay. I'm guessing that there is more to this, but I'm not sure what that would be.
Assuming the neutron in a deuteron did undergo beta decay, what are the resulting products? What is the combined (rest) mass of the products? How does that mass compare with the rest mass of the deuteron.

One would use a similar approach in following haruspex's suggestion.
 
Thank you both.
So because the resulting atom would consist of 2 protons and 0 neutrons it would be too unstable?
 
pbonnie said:
Thank you both.
So because the resulting atom would consist of 2 protons and 0 neutrons it would be too unstable?
As Astronuc says, you should look at the energy balance. Also, as I understand it, Beta decay is of two types; with the other type you'd get two neutrons and no protons.
 

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