Beta decay of deuterium and triterium

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Homework Help Overview

The discussion revolves around the beta decay of deuterium and tritium, specifically addressing why deuterium cannot undergo beta decay or produce a stable nucleus, while tritium can. Participants explore the stability of these isotopes and the implications of potential decay processes.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the stability of deuterium as a stable isotope of hydrogen and question the conditions under which beta decay could occur. There are inquiries about the resulting products of decay and the mass comparisons involved.

Discussion Status

The discussion is active, with participants offering insights into the nature of the resulting nuclei from potential decay processes. Some guidance is provided regarding the energy balance involved in these transformations, and multiple interpretations of the decay processes are being explored.

Contextual Notes

There is mention of a lack of detailed explanation in the lesson regarding the decay processes, and participants are attempting to reconcile their understanding with the information available to them.

pbonnie
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Homework Statement


Explain why deuterium cannot undergo beta decay or produce a stable nucleus, while tritium can.


Homework Equations


n/a


The Attempt at a Solution


There was nothing in the lesson that really explained this, and the only reason I can find online is because deuterium is a stable isotope of hydrogen so it does not decay. I'm guessing that there is more to this, but I'm not sure what that would be.
 
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Consider what the resulting nucleus could consist of. Tritium can convert N->P making He-3.
 
pbonnie said:

Homework Statement


Explain why deuterium cannot undergo beta decay or produce a stable nucleus, while tritium can.

The Attempt at a Solution


There was nothing in the lesson that really explained this, and the only reason I can find online is because deuterium is a stable isotope of hydrogen so it does not decay. I'm guessing that there is more to this, but I'm not sure what that would be.
Assuming the neutron in a deuteron did undergo beta decay, what are the resulting products? What is the combined (rest) mass of the products? How does that mass compare with the rest mass of the deuteron.

One would use a similar approach in following haruspex's suggestion.
 
Thank you both.
So because the resulting atom would consist of 2 protons and 0 neutrons it would be too unstable?
 
pbonnie said:
Thank you both.
So because the resulting atom would consist of 2 protons and 0 neutrons it would be too unstable?
As Astronuc says, you should look at the energy balance. Also, as I understand it, Beta decay is of two types; with the other type you'd get two neutrons and no protons.
 

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