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Binding energy of 2p electron in Lithium

  1. May 16, 2012 #1
    1. The problem statement, all variables and given/known data

    Explain why the 2p state for Lithium is close to the n=2 state for Hydrogen and why the 2s state is much higher. (5.4eV)

    3. The attempt at a solution

    I think that for 2p state (n=2, l=1) we can model (for some reason) the Lithium valence electron like the electron orbiting Hydrogen. My guess is that we cannot do this for the l=0 state (2s) but I am unsure why this is the case.
     
  2. jcsd
  3. May 16, 2012 #2
    Could it be that because the electron has angular momentum that it is less influenced by the other electrons in the n=1 state and we can treat the 2 electron 3 proton system as 1 proton?
     
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