Binomial probability, similar to lottery problems.

AI Thread Summary
The discussion focuses on calculating the probability of scoring points based on drawing counters from a bag containing green and red counters without replacement. The problem involves determining the probabilities of scoring 0 to 5 points based on the number of green counters drawn. The initial approach using binomial probability with replacement is deemed straightforward, but the challenge arises when considering the lack of replacement, which complicates the calculations. The correct method involves calculating the number of ways to achieve a specific score by drawing a combination of green and red counters and dividing by the total combinations possible. Understanding this method is essential for solving similar problems that resemble lottery scenarios.
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Homework Statement


An opaque bag contains 10 green counters, and 20 red ones. One counter is drawn at random and not replaced: green scores one, red scores zero. Five counters are drawn.

Find the probability of scoring 0, 1, 2, 3, 4, 5 points.


Homework Equations





The Attempt at a Solution


I found it pretty straighforward to work out with replacement, as it is just the simple binomial probability. But when the counters aren't replaced, surely the order counts, so i tried replacing nCr with nPr though this gave me the completely wrong answer. i know this resembles the lottery problem, but i don't understand what to do when there are only 2 distinguishable groups.
 
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If you score n points, that means you drew n green and 5-n red counters. What you want to do is figure out the number of ways you can do that and divide by the total number of ways you can draw five items from thirty.
 
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